110=3x^2+7x

Solution for 110=3x^2+7x equation:

110=3x^2+7x

We move all terms to the left:

110-(3x^2+7x)=0

We get rid of parentheses

-3x^2-7x+110=0

a = -3; b = -7; c = +110;
Δ = b2-4ac
Δ = -72-4·(-3)·110
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-37}{2*-3}=\frac{-30}{-6}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+37}{2*-3}=\frac{44}{-6}
=-7+1/3
$